Question

the length width height of the room are 7 ,8, 9 m respectively what is the total area of the wall​

Answer 1

Given :

• Length of the room = 7 m.
• Width of the room = 8 m.
• Height of the room = 9 m.

To find :

• Total area of the wall.

Solution :

• Length = 7 m.
• Width = 8 m.
• Height = 9 m.

We know,

${\boxed{\green{\bold{Total\:area\: of\: the\:wall=2(Length+Width)\times\: Height}}}}$

$\implies\sf{Total\:area\:of\: the\:wall=2(7+8)\times\:9\:m^2}$

$\implies\sf{Total\:area\:of\: the\:wall=2\times\:15\times\:9\:m^2}$

$\implies\sf{Total\:area\:of\: the\:wall=270\:m^2}$

Therefore the total area of the wall is 270 m².

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More Information :-

✪ Cuboid ✪

1. Total surface area of cuboid =

2(l×b + l×h + w×h)

2. Diagonal of cuboid =

$\sqrt{l^2+w^2+h^2}$

3. Volume of cuboid =

Length × Width × Height

[ where l = length ,w = width, h = Height]

✪ Cube ✪

1. TSA of cube = 6a²

2. Diagonal of cube = a√3

3. Volume of cube = a³

[ Where a = side ]

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Answer 2

AnsWer :

270 m².

Given :

• Length = 7m.
• Width = 8m.
• Height = 9m.

Solution :

We have,

$\tt The \: total \: area \: of \: Wall =2(l + b) \times h.$

$\tt\longmapsto A_{Wall} = 2( 7 + 8 ) 9.$

$\tt\longmapsto A_{Wall} = 2(15) 9.$

$\tt\longmapsto A_{Wall} = 270 \: {m}^{2} .$

Therefore, the value of Wall be 270 m².

$\rule{120}1$

Some Formula :

Cube,

• TSA => 6a²
• CSA => 4a²
• Volume => a³
• Diagonal => √3a

Cuboid,

• TSA => 2( lb + bh + hl )
• CSA => 2( l + b )h
• Volume => l* b * h
• Diagonal² => l²+ h² + b²