Question

The lengths of diagonals of a rhombus are 16cm and 12cm. The side of the rhombus is
______cm

Answer 1

Answer: A rhombus ABCD is there, the diagonals bisect each other at a point O. Let the side of rhombus be AB.

1st diagonal = AC =16 cm

2nd diagonal = BD = 12 cm

AO = AC/2 = 16/2= 8 cm

OB = BD/2 = 12/2 = 6 cm

By Pythagoras theorem,

AO^2+ OB^2 = AB^2

8^2+6^2 = AB^2

64+36 = AB^2

100 = AB^2

√100 = AB

10 cm = AB

So the length of the side is 10 cm.

Answer 2

Answer:

10 cm

Step-by-step explanation:

let abcd a rhombus , and the diagonals bisect each other at 90 degree at the point O

Let AC = 16 CM

BD = 12 cm

take triangle AOB

AO= AC/2=8cm

OB=BD/2=6cm

by pythagorus theorm

H^2= B^2+P^2

AB^2=AO^2+OB^2

8^2+6^2=AB^2

64+36=AB^2

100=AB^2

root 100= AB

AB=10

length of side is 10 cm