Question

The lengths of diagonals of a rhombus are 24 cm and 32 cm. Find the length of its sides
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Answer 1

In rhombus (side)^2=(d1/2)^2+(d2/2)^2

d1=24, d2=32

A/Q

(side)^2=(24/2)^2+(32/2)^2

(side)^2=576/2+1024/2

(side)^2=1600/4

(side)^2= under root 1600/4

side= 40/2

side=20cm

Step-by-step explanation:

Here d represents diagonals.