the lengths of parallel sides of a trapezium are in ratio 7:5 and the distance between them is 14cm.if the area if the trapezium is 252cmsq., find the length of parallel sides.
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hii!!!
here's ur answer...
given the height ( distance between the parallel sides) is 14cm.
let the two parallel sides be 7x and 5x.
area of the trapezium = 252cm²
therefore 1/2×h(b1+b2) = 252cm²
=> 1/2×14(7x+5x) = 252cm²
=> 7×12x = 252cm²
=> 12x = 252/7
=> 12x = 36
=> x = 36/12
=> x = 3
hence, length of the parallel sides are :-
→ 7x = 7×3
= 21cm
→ 5x = 5×3
= 15cm
VERIFICATION:-
area of the trapezium = 1/2×h(b1+b2)
= 1/2×14(21+15)
= 7×36
= 252cm²
hence verified
hope this helps..!
here's ur answer...
given the height ( distance between the parallel sides) is 14cm.
let the two parallel sides be 7x and 5x.
area of the trapezium = 252cm²
therefore 1/2×h(b1+b2) = 252cm²
=> 1/2×14(7x+5x) = 252cm²
=> 7×12x = 252cm²
=> 12x = 252/7
=> 12x = 36
=> x = 36/12
=> x = 3
hence, length of the parallel sides are :-
→ 7x = 7×3
= 21cm
→ 5x = 5×3
= 15cm
VERIFICATION:-
area of the trapezium = 1/2×h(b1+b2)
= 1/2×14(21+15)
= 7×36
= 252cm²
hence verified
hope this helps..!
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