the lengths of the diagonals of a rhombus are 16cm and 12cm. find the length of each side of the rhombus
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The sides are each 10 cm and the perimeter is 40 cm.
Solution :
Let AC=12cmAC=12cm
BD=16cmBD=16cm
BO=12BO=12BDBD
=8cm=8cm
AD=12AD=12AC=6cmAC=6cm
Now in Right ΔAOBΔAOB
AB2=AO2+OB2AB2=AO2+OB2
=62+82=62+82
=36+64=36+64
=100=100
=102=102
AB=10cmAB=10cm
The length of each of its sides =10cm=10cm
Answer : 10cm
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Solution :
Let AC=12cmAC=12cm
BD=16cmBD=16cm
BO=12BO=12BDBD
=8cm=8cm
AD=12AD=12AC=6cmAC=6cm
Now in Right ΔAOBΔAOB
AB2=AO2+OB2AB2=AO2+OB2
=62+82=62+82
=36+64=36+64
=100=100
=102=102
AB=10cmAB=10cm
The length of each of its sides =10cm=10cm
Answer : 10cm
hope it's helps pls give it brainliest and follow me please
Ashwin770:
how bro can you please explain me
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Hope it helps ! mark as brainliest
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