The lengths of the diagonals of a rhombus are 30 cm and 40 cm find the side ofthe rhombus
Answers
Answered by
2
Diagonals of a rhombus are perpendicular bisectors of each other
Suppose the name of the rhombus is ABCD, then AC and BD are it's diagonals which measure 30cm and 40cm respectively and they meet at point O.
Therefore, AO=15cm and BO=20cm
In ∆AOB,
angle AOB=90°
AB2(square)=AO2+BO2
=225+400
=625
AB=25cm
Therefore side of the rhombus measures 25cm
Suppose the name of the rhombus is ABCD, then AC and BD are it's diagonals which measure 30cm and 40cm respectively and they meet at point O.
Therefore, AO=15cm and BO=20cm
In ∆AOB,
angle AOB=90°
AB2(square)=AO2+BO2
=225+400
=625
AB=25cm
Therefore side of the rhombus measures 25cm
Answered by
1
HEY USER..
HERE IS YOUR ANSWER.
Let the side of rhombus be ABCD
ACC TO PYTHOGORAS THEOREM,
p^2 + b^2 = h^2
(the diagonal AC bisect BD)
20^2 + 15^2 = h^2
625 = h^2
h = 25
Hence, the each side= 25 cm
Hope this helps you!
HERE IS YOUR ANSWER.
Let the side of rhombus be ABCD
ACC TO PYTHOGORAS THEOREM,
p^2 + b^2 = h^2
(the diagonal AC bisect BD)
20^2 + 15^2 = h^2
625 = h^2
h = 25
Hence, the each side= 25 cm
Hope this helps you!
Similar questions