the lengths of the diagonals of a rhombus are in the ratio 6:8. If its perimeter is 40cm . Find the length of the shower diagonal
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As we know that the perimeter of rhombus = 4 × side
Here,
40 = 4 × side
40/4 = side
10 side
then,
Let the length of diagonals be 6x and 8x
by pythagoras theorem,
10^2 = (6x/2)^2 +(8x/2)^2
100 = 9x^2 + 16x^2
100 = 25x^2
100/25 = x^2
4 = x^2
2= x
Now,
length of diagonals is:-
6 × 2 =12cm
and
8 × 2 =16cm
Length of shorter diagonal is 6x i.e. 12cm
Hope This Helps :)
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