Question

The lengths of the parallel sides of a trapezium are 19 cm and 13 cm and its area is 128 cm2. The distance between the parallel sides is

Answer 1

Answer:

GIVEN :

• Parallel side of trapezium = 19 cm and 13 cm
• Area = 128 cm²

TO FIND :

Distance between them

SOLUTION :

We know that

$\large \sf \: Area = \dfrac{1}{2} \bigg(a + b \bigg) \times h$

Let the height be x

$\large \sf \to \: 128 = \dfrac{1}{2} \bigg(19 +13 \bigg) \times h$

$\large \sf \to \: 128 \times 2 = \bigg(19 + 13 \bigg) \times h$

$\large \sf \to \: 256 = 32 + h$

$\large \sf \to \: \dfrac{256}{32} = h$

$\large \sf \to \: 8 = h$