Question

The lengths of the parallel sides of a trapezium are 5, 9 and its height is 7. Find its area.

Answer 1

Answer:

Appropriate Question :-

• The length of the parallel sides of a trapezium are 5 m and 9 m and its height is 7 m. Find its area.

Given :-

• The length of the parallel sides of a trapezium are 5 m and 9 m and its height is 7 m.

To Find :-

• What is the area of a trapezium.

Formula :-

$\clubsuit$ Area Of Trapezium Formula :

$\footnotesize \bigstar \: \: \sf\boxed{\bold{\pink{Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: Parallel\: Sides) \times Height}}}\: \: \: \bigstar$

Solution :

Given :

• Length of parallel sides = 5 m and 9 m
• Height = 7 m

According to the question by using the formula we get,

$\implies \sf\bold{\blue{Area_{(Trapezium)} =\: \dfrac{1}{2} \times (a + b) \times h}}$

$\footnotesize \implies \bf Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: Parallel\: Sides) \times Height$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{1}{2} \times (5 + 9) \times 7$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{1}{2} \times 14 \times 7$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{1}{2} \times 98$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{1 \times 98}{2}$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{\cancel{98}}{\cancel{2}}$

$\implies \sf Area_{(Trapezium)} =\: \dfrac{49}{1}$

$\implies \sf\bold{\red{Area_{(Trapezium)} =\: 49\: m^2}}$

$\sf\bold{\purple{\underline{\therefore\: The\: area\: of\: trapezium\: is\: 49\: m^2\: .}}}$

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Answer 2

$\begin{gathered}\footnotesize\bigstar \: \: \sf\boxed{\bold{\pink{Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: Parallel\: Sides) \times Height}}}\: \: \: \bigstar\\\end{gathered} \\\begin{gathered}\footnotesize \: \sf\boxed{\bold{\blue{Solution :}}}\end{gathered}\\\begin{gathered}\footnotesize \: \sf\boxed{\bold{\orange{Given :}}} \end{gathered} \\\rm{ Length \: of \: parallel \: sides = 5 \: m \: and \: 9 \: m \: Height = 7 \: m} \\\rm{According \: to \: the \: question \: by \: using \: the \: formula \: we \: get,} \\\begin{gathered} \pink{\implies \sf\bold{{Area_{(Trapezium)} = \dfrac{1}{2} \times (a + b) \times h}}}\end{gathered} \\ \begin{gathered}\footnotesize \implies \bf Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: Parallel\: Sides) \times Height\end{gathered} \\\begin{gathered}\implies \sf Area_{(Trapezium)} =\: \dfrac{1}{2} \times (5 + 9) \times 7\end{gathered}\\\begin{gathered}\implies \sf Area_{(Trapezium)} =\dfrac{1}{2} \times 14 \times 7\end{gathered}\\\begin{gathered}\implies \sf Area_{(Trapezium)} =\: \dfrac{1}{2} \times 98\end{gathered}\\\begin{gathered}\implies \sf Area_{(Trapezium)} =\: \dfrac{1 \times 98}{2}\end{gathered}\\\begin{gathered}\implies \sf Area_{(Trapezium)} = \dfrac{\cancel{98}}{\cancel{2}}\end{gathered} \\\begin{gathered}\implies \sf Area_{(Trapezium)} = \dfrac{49}{1}\end{gathered} \\\begin{gathered}\implies\sf\bold{{Area_{(Trapezium)} =\: 49\: m^2}}\end{gathered}\\\begin{gathered}\sf\bold{\red{\underline{\therefore\: The\: area\: of\: trapezium\: is\: 49\: m^2\: .}}}\end{gathered}$