Question

The lengths of the rectangle have been measured to the nearest tenth of a centimetre work out the following figures
(A) the upper bound for the area of the rectangle
(B) the lower bound for the perimeter of the rectangle 87.3 and 51.8

Answer 1

Given:

The lengths of the rectangle have been measured to the nearest tenth of a centimetre 87.3 and 51.8  

To find:

Work out the following figures

(A) the upper bound for the area of the rectangle

(B) the lower bound for the perimeter of the rectangle  

Solution:

From given, we have,

The length of the rectangle = l = 87.3 cm

The breadth of the rectangle = b = 51.8 cm

(A)

Area of the rectangle = lb = 87.3 × 51.8 = 4522.14 cm²

The upper bound for the area of the rectangle = 4522.14 + 100/2 = 4522.14 + 50 = 4572.14 cm²

(B)

Perimeter of the rectangle = 2(l + b) = 2(87.5 + 51.8) = 278.2 cm

The lower bound for the perimeter of the rectangle = 278.2 - 10/2 = 278.2 - 5 = 273.2 cm

(A) The upper bound for the area of the rectangle is 4572.14 cm²

(B) The lower bound for the perimeter of the rectangle is 273.2 cm