The lengths of the sides of a triangle are 5 cm, 12 cm and 13 cm. Find the length of perpendicular from the opposite vertex to the side whose length is 12cm ???
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it is clear that the triangle is a right angled triangle.
Let AB=12 cm BC=5 cm and AC=12 cm
Now a perpendicular is drawn from A to AC.
ar(ABC)=½AB⋅BC=½CA• BD.BD=AB⋅BCCA
Putting the respective values of the sides we get,
B/D=60/12cm
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