The lengths of the sides of a triangle are 5cm, 12cm and 13cm, what will be the length of the perpendicular from the vertex opposite the larger side to its side?
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Answer:
Here,
a=5,b=12,c=13
s=
2
1
(a+b+c)=15
Area of the triangle, A =
s(s−a)(s−b)(s−c)
A=
15(15−5)(15−12)(15−13)
A=30 cm
2
Let p be the length of perpendicular. Then,
A=
2
1
×13×p
Therefore,
2
1
×13×p=30
p=
13
60
cm
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