The lengths of the sides of a triangle are in a ratio of 3 : 4 : 5 and its perimeter is 144 cm. Find the area of the triangle and the height corresponding to the longest side?
Answers
hi mate,
answer :The area of triangle is 864 cm² and the height corresponding to the longest side is 28.8 cm.
Step-by-step explanation:
The length of the sides of a triangle are in the ratio 3:4:5. Let the length of sides be 3x,4x,5x.
It is given that the perimeter of the triangle is 144 cm.
Let
the side = 3 x 4 x 5 x
144 = 3x + 4 x + 5 x
x = 144 / 12
x = 12
now we multiply by
3* 12 = 36 Cm = a
4* 12=48cm = b
5* 12=60cm = c = base....
S = a+b+c/2
36 + 48 + 60/2
144/2 = 72
triangle area = √ s (s - a) (s-b) ( s-c)
triangle area
= √ 72 (72-36) (72-48) (72-60)
triangle area = √72 (36) (24) (12)
triangle area = √746496
triangle area=864cm²
triangle area = ½ * base * height
864 = ½* 60 *height
864 = 30 *height
height = 864/30 = 28.8 cm
The height corresponding to the longest side is 28.8 cm.
i hope it helps you..
Here we have,
Ratio = 3 : 4 : 5
Perimeter = 144 cm
Assume,
Sides,
a = 3p , b = 4p and c = 5p
Now,
Perimeter of Triangle = a + b + c
144 = 3p + 4p + 5p
12p = 144
p = 144/12
p = 12
Here,
Sides of triangle are :-
a = 3p = 3 × 12 = 36 m
b = 4p = 4 × 12 = 48 m
c = 5p = 5 × 12 = 60 m
Now,
Semi Perimeter of Triangle,
s = (a + b + c)/2
s = (36 + 48 + 60)/2
s = 144/2
s = 72 m
Now,
Using Heron formula :-
A = √s(s - a)(s - b)(s - c)
A = √72(72 - 36)(72 - 48)(72 - 60)
A = √72 × (36) × (24) × (12)
A = √(36 × 2) (36) (12 × 2) × 12
A = √(36 × 36 × 12 × 12) × (2 × 2)
A = 36 × 12 × 2
A = 72 × 12
A = 864 cm²
Now, here,
Longest side = 60 cm
A = ½ x Base x altitude
864 = ½ × 60 × altitude
864 = 30 × altitude
altitude = 864 / 30
altitude = 28.8 cm