The lengths of the sides of a triangle are integrals, and its area is also integer. One side is
21 and the perimeter is 48. Find the shortest side.
How to find c to get 10
Answers
Answered by
26
Let the sides of the triangle be a, b and c
Thus
according to question
a = 21
also perimeter = 48
Thus
a + b + c = 48
21 + b + c = 48
b + c = 48 - 21
b + c = 27
Thus we can clearly see that the largest side is = 21
Thus Smallest side b = 27 - c
Thus
according to question
a = 21
also perimeter = 48
Thus
a + b + c = 48
21 + b + c = 48
b + c = 48 - 21
b + c = 27
Thus we can clearly see that the largest side is = 21
Thus Smallest side b = 27 - c
How to find c to get 27 think 27-c=27-17so 10 is answer
Answered by
32
Hi friends i am sridhar and i think it may be helpfull
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