The lengths of three medians of a triangle are 9 cm 12 cm and 15 cm find the area of the triangle
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a=9cm
b=12cm
c=15cm
perimeter of triangle=a+b+c=2s
2s=9+12+15
s=36/2=18
Area of triangle=androot[s(s-a)(s-b)(s-c)
=androot[18(18-9)( 18-12)( 18-15)]
=androot( 18×9×6×3)
=androot(2×3×3×3×3×2×3×3)
=androot(2×3×3×3)^2
=54cm^2
b=12cm
c=15cm
perimeter of triangle=a+b+c=2s
2s=9+12+15
s=36/2=18
Area of triangle=androot[s(s-a)(s-b)(s-c)
=androot[18(18-9)( 18-12)( 18-15)]
=androot( 18×9×6×3)
=androot(2×3×3×3×3×2×3×3)
=androot(2×3×3×3)^2
=54cm^2
Answered by
2
The area of triangle is 72 square cm
Solution:
Given that,
The lengths of three medians of a triangle are 9 cm 12 cm and 15 cm
To find: Area of triangle
The area of triangle is given as:
Therefore,
Thus area of triangle is 72 square cm
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