The lengths of two adjacent sides of parallelogram are 51cm and 37cm respectively. One of its diagnols is 20cm. Find the area of the parallelogram
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Let we consider ABCD is parallelogram
in which AB & BC are two adjacent side
where,AB=51cm and BC=37cm
One diagonal is AC=20 cm
Finding area of ∆ABC
Now,
s=(a+b+c)/2
=(51+37+20)/2
=54cm
area of ∆ABC=√(s(s-a)(s-b)(s-c))
=√(54(54-51)(54-37)(54-20))
=√93636
=306cm²
area of parallelogram=2area of ∆ABC
=306×2
area of llgm ABCD=612cm²
in which AB & BC are two adjacent side
where,AB=51cm and BC=37cm
One diagonal is AC=20 cm
Finding area of ∆ABC
Now,
s=(a+b+c)/2
=(51+37+20)/2
=54cm
area of ∆ABC=√(s(s-a)(s-b)(s-c))
=√(54(54-51)(54-37)(54-20))
=√93636
=306cm²
area of parallelogram=2area of ∆ABC
=306×2
area of llgm ABCD=612cm²
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