the lengts of sides of a triangle are in the ratio of 1:2:3.find the length of its sides,if the perimeter is 300cm.
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his side is 50,100, and 150 because X+2x+3x =300 then X=50
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ratios of sides of a triangle = 1:2:3
let the ratios of sides of triangle be 1x, 2x ,3x
the perimeter of a triangle = side 1 +2+3
300=1x + 2x +3x
300=6x
300/6=x
50=x
therefore the value of first side of the triangle =1*50=50 cm
second side of the triangle =2*50=100cm
third side of the triangle =3*50=150 cm
.hope this will help u. plz mark as brainlest answer.........
let the ratios of sides of triangle be 1x, 2x ,3x
the perimeter of a triangle = side 1 +2+3
300=1x + 2x +3x
300=6x
300/6=x
50=x
therefore the value of first side of the triangle =1*50=50 cm
second side of the triangle =2*50=100cm
third side of the triangle =3*50=150 cm
.hope this will help u. plz mark as brainlest answer.........
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