the lentgh of two sides of a triangle are 4 cm and 6 cm. Between what two measures should the length of the third side fall?
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when you apply the cosine theorem
the data that you have to introduce is:
side AB = 4,
side BC = 6
Side AC = sqrt (AB^2+BC^2–2AB*BC*cosine (angle between AB and BC)
angle between AB and BC= 0 and 180, because I pretend to evaluate all the possible triangles that can be created, after
Then you will get a lot of possible triangles, you just have to change the angle between AB and BC
and the values of the third side range from 2 to 10, as you may notice, the superior and inferior limits is no more than the difference and the sum of both sides.
the data that you have to introduce is:
side AB = 4,
side BC = 6
Side AC = sqrt (AB^2+BC^2–2AB*BC*cosine (angle between AB and BC)
angle between AB and BC= 0 and 180, because I pretend to evaluate all the possible triangles that can be created, after
Then you will get a lot of possible triangles, you just have to change the angle between AB and BC
and the values of the third side range from 2 to 10, as you may notice, the superior and inferior limits is no more than the difference and the sum of both sides.
kauser7:
tell me with numbers
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