Question

the letters of the word lottery written one each on cards are put in a box a card is taken out of the box find the probability of getting a card with l​

Answer 1

Given:

The given word is "lottery"

And the letters of the word are written each on a card and were put in a box

To find:

We have to find the probability of getting a card with letter "l" when drawn from the box

Solution:

we know that probability of an event = (number of favourable outcomes)

                                                                 ÷(Total outcomes)

Now total outcomes= 7  

Because there are 7 letters in the word "lottery"

Number of favorable outcomes=Number of "l" s in the word = 1

Probability= 1/7

∴Probability of getting a card with letter "l" is  $\frac{1}{7}$.

Answer 2

Step-by-step explanation:

Distance covered by it in 12 sec.

Law used:-

{\boxed{\bf{Second\:Law\:of\: Motion: S=ut+\dfrac{1}{2}at^2}}}

SecondLawofMotion:S=ut+

2

1

at

2

Here,

S = Distance

u = Initial Velocity

a = Acceleration

t = Time Taken

Solution:-

Using the Second Law of Motion,

\bf \implies\:S=ut+\dfrac{1}{2}at^2⟹S=ut+

2

1

at

2

Here,

u = 0

S = 15m

t = 3 sec

Putting the values,

\sf \implies\:15=0\times3+\dfrac{1}{2}\times a \times 3^2⟹15=0×3+

2

1

×a×3

2

\sf \implies\:15=\dfrac{1}{2}\times a \times 9⟹15=

2

1

×a×9

\sf \implies\:9a=15\times2⟹9a=15×2

\sf \implies\:a=\dfrac{30}{9}⟹a=

9

30

{\boxed{\bf{\implies\:a=\dfrac{10}{3}\:ms^{-2}}}}

⟹a=

3

10

ms

−2

Now, Distance covered by it in 12 sec:-

Again, Using Second Law of Motion:-

\bf \implies\:S=ut+\dfrac{1}{2}at^2⟹S=ut+

2

1

at

2

Here,

u = 0

a = 10/3 m/s²

t = 12 sec

Putting values,

\sf \implies\:S=0\times12+\dfrac{1}{2}\times \dfrac{10}{3} \times 12^2⟹S=0×12+

2

1

×

3

10

×12

2

144⟹S=

2

1

×

3

10

72⟹S=

3

10

24⟹S=10×24

⟹S=240m

Hence, The Distance covered by the given body in 12 sec is 240m.