the lid of a rectangular box of side 40 cm by 10 cm is sealed all around with tape. What is the length of the tape required?
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Answer:
The total length of tape required = Perimeter of the rectangle
= 2(lenght+breadth)
= 2(40+10)
= 2(50)
= 100 cmn
= 1 meter
Therefore, total length of tape required is 100 cm or 1 meter.
Answered by
2
The total length of tape required = Perimeter of the rectangle
= 2(lenght+breadth)
= 2(40+10)
= 2(50)
= 100 cmn
= 1 meter
Therefore, total length of tape required is 100 cm or 1 meter.
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