the lid of rectangular box of sides 40cm by10cm is sealed all round with tape .what is length of tape required.
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Answered by
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Answer:
length of tape required=perimeter of rectangle
=2(l+b)
=2(40+10)
=2(50)
=100 cm
Answered by
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Step-by-step explanation:
Length of tape =perimeter of rectangle
=2(l+b)
=2(40+10)
=2(50)
=100cm
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