Question

The life time of a component measured in hours follows Weibull distribution with parameter a= 0.2,b=0.5. Find the mean life time of the component.

Answer 1

The quarrel was between the mountain and the

Answer 2

The mean life time of the component 50 hours.

Given,

a=0.2

b=0.5

To Find,

the mean life time of the component.

Solution:

We know that,

E(X)=$a^{-1/b}$ Γ(1+1/b)

E(X)=$0.2^{-1/0.5}$Γ(1+ 1/0.5)

E(X)=25Γ(1+2)

E(X)=25Γ(3)

E(X)=25*2!

E(X)=50 hours

thus, the mean life time of the component 50 hours.

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