Question

The light of wavelength 600 nm is incident normally on a slit of width 3mm. Calculate the
linear width of central maximum on a screen kept 3m away from the solid.​

Answer 1

Wavelength (L) = 600nm = 6×10^-7

and, a = 3mm = 3×10^-3

and, D = 3m

Let width of central maxima = w

Therefore, w = 2DL/a

w = (2×3×6×10^-7)/3×10^-3

w = 12 × 10-^4 m = 1.2 mm

Thus, width of central maxima = 1.2 mm

Answer 2

Answer:

Explanation:

The light of wavelength = 600 nm *$10^{-9} m$

slit of width = 3mm * $10^{-3}$

distance of the screen from the slit, D= 3m

Now,

​linear width of central maximum=$\frac{2D}{d}$

                                                 =$\frac{2*3*600*10^-9}{3*10^-3}$

                                                = 1.2mm