Question

the light strings of length 4cm and 3cm are tied to a bob of a weight 500gm the free ends of the strings are tied to pegs in the same horizontal line and seperated by 5vm te ratio of tension in the longer string to that in the shorter string is?

Answer 1

T1cos θ = mg
T2cos( 90− θ )= mg
dividing above two equations we get,
T1cosθ T2sin θ  = 1
or, T1 T2  = tanθ
 from the diagram we can see sin α =3by5
so α  = sin raise to −1(3by5)
α  = 370
so from the left side dotted triangle we get
 90 degree  + α  +θ  = 180 degree
 or θ   = 180 degree −90 degree −37 degree = 53 degree
hence we have
 T1 T2  = tanθ
 T1 T2  = tan53o
 T1 T2  =1.33 

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