Question

The line 3x -2y = k meets the circle x² + y² = 4r² at only one point, if k² =

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Answer 1

Answer:

Step-by-step explanation:

The line 3x -2y = k meets the circle x² + y² = 4r² at only one point, if k² =

Answer 2

Solution

Let us assume that one zeros of the given quadratic equationbe(2x² – 3x + k) be α

Hence the other zero is reciprocal of the zero. So the other zero is 1/α

As per the given equation

a = 2 b = -3 c = k

So, α x 1/α = c/a

1 = k/2

k = 2

The value of k is 2