Question

The line 4x-3+12=0 meets x-axis at A. Write the coordinates of A..
Determine the equation of the line through A and perpendicular to
4x-3 + 12 = 0

Answer 1

4 x + 3 - 12 = 0 =>4 x = 9. =>x=9/4
so the coordinates of a is (9/4,0)
the equation of the line through a and perpendicular to 4 x -3 + 12 = 0 is ->
3x+4+k=0
=>k=-43/4

show the equation is 12x+16-43=0

Answer 2

Answer:

coordinates of A (-3, 0)

and Equation of line is 3x + 4y + 9 = 0

Step-by-step explanation:

(i) Since line 4x - 3y + 12 = 0 meets X-axis at A.

Let coordinates of A be (x, 0)

Hence put y = 0 in equation of line

    4x - 3(0) + 12 = 0

      4x = -12

       x = -3

Hence coordinates of A be (-3, 0).

(ii) Now, Slope of line  4x - 3y + 12 = 0 is 4/3

Since both the lines are perpendicular,

slope of given line  * slope of required line = -1

Therefore, Slope of required line = -3/4

Hence required equation of line passing through A and having slope -3/4

y - 0 = -3/4 (x + 3)

4y = -3x - 9

3x + 4y + 9 = 0