The line ab has a mid point (2,5) a has coordinates of (1,2) find the coordinates of b
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Mid point = P(2,5)
A(x1 , y1) = (1 , 2)
B(x2 , y2)
2 = (x1+x2)/2
=> 2*2 = 1 + x2
=> 4-1 = x2
=> x2 = 3
Similarly,
5 = (y1 + y2)/2
=> 10 = 2 + y2
=> y2 = 10 - 2
=> y2 = 8
.•. point B is B(3,8)
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