Question

the line joining the mid point of one diagonal to one of the other two vertices in a regular quadrilateral is 70cm . What is the length of the other diagonal ? pls explain cuz I know the answer​

Answer 1

Answer:

ʜᴇʀᴇ ɪs ʏᴏᴜʀ ᴀɴsᴡᴇʀ⬇️

Step-by-step explanation:

⬆️ ʟᴇᴛ ᴀʙᴄᴅ ᴛʜᴇ ʀᴇᴄᴛᴀɴɢʟᴇ ɪɴ ᴡʜɪᴄʜ ᴀᴄ ʙᴇ ɪᴛs ᴏɴᴇ ᴏғ ᴛʜᴇ ᴅɪᴀɢᴏɴᴀʟ

➡️ ʟᴇᴛ ᴏ ʙᴇ ᴛʜᴇ ᴍɪᴅ ᴘᴏɪɴᴛ ᴏғ ᴀᴄ

ɴᴏᴡ ᴏᴅ, = 70ᴄᴍ

➡️ ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ ᴅɪᴀɢᴏɴᴀʟ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ ʙɪsᴇᴄᴛ ᴇᴀᴄʜ ᴏᴛʜᴇʀ.

➡️ sᴏ, ᴅɪᴀɢᴏɴᴀʟ ʙᴅ ᴡɪʟʟ ɪɴᴛᴇʀsᴇᴄᴛ ᴀᴄ ᴀᴛ ᴏ.

ɴᴏᴡ ᴏʙ = ᴏᴅ= 70ᴄᴍ

sᴏ ʙᴅ = ᴏʙ + ᴏᴅ= 140ᴄᴍ

➡️ ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ ᴅɪᴀɢᴏɴᴀʟ ᴏғ ʀᴇᴄᴛᴀɴɢʟᴇ ᴀʀᴇ ᴇǫᴜᴀʟ sᴏ,

ᴀᴄ = 140ᴄᴍ

Answer 2

$\large{\boxed{\texttt{Answer:}}}$

AC = 140 cm

$\Large{\underline{\mathfrak{\red{EXPLANATION:}}}}$

$\mapsto$ Let ABCD be the rectangle in which AC is one the diagonal.

$\mapsto$ Let 'O' be the midpoint of AC.

Now,

$\bold{\texttt{OD\:=\:70\:cm}}$

WE KNOW THAT DIAGONAL OF RECTANGLE BISECT EACH OTHER AT EQUAL POINTS.

So, diagonal BD will intersect AC at O.

Now

$\mapsto$ $\bold{\texttt{OB\:=\:OD\:=\:70\:cm}}$

$\therefore$ $\bold{\texttt{BD\:=\:OB\:+\:OD\:=\:140\:cm}}$

$\mapsto$ Also we also we know that diagonals of rectangle are equal.

So, ${\bold{\boxed{\texttt{AC\:=\:140\:cm}}}}$