The line joining the mid-points of two chords
of a circle passes through its centre. Prove
that the chords are parallel.
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Answer:
Given : E and F are mid points of 2 chords AB and CD respectively.
Line EF passes through centre.
To prove : AB||CD
∠OFC = ∠OEA = 90° as line drawn through the centre to bisect the chord is ⟂ to chord considering EF as traversal for lines AB and CD as alternate interior angles on same side are equal.
Therefore, AB || CD
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