Math, asked by sharanyalanka7, 3 days ago

The line segment joining A(3,0),B(5,2) are rotated about a point A in anticlockwise sense through an angle π/4 and B move to C. If point D be the reflection of C in Y - axis then D=

Answers

Answered by mathdude500
13

Given :-

  • The line segment joining A(3,0),B(5,2) are rotated about a point A in anticlockwise sense through an angle π/4 and B move to C.

To Find :-

  • Reflection of Coordinates C under y - axis . i.e. D

Solution :-

Given that,

  • Coordinates of A (3, 0)

and

  • Coordinates of B (5, 2)

We know,

Slope of a line joining two points A (a, b) and B (c, d) is represented by m and is given by

\bf :\longmapsto\:m = \dfrac{d - b}{c - a}

Let Slope of AB be m, then

\rm :\longmapsto\:m = \dfrac{2 - 0}{5 - 3}

\rm :\longmapsto\:m = \dfrac{2}{2}

\bf\implies \:m = 1

Let assume that line AB makes an angle p with positive direction of x axis.

\rm :\implies\:tanp = 1

\rm :\implies\:tanp = tan45\degree

\bf\implies \:p = 45\degree

Since,

  • Line AB is rotated through an angle of 45° with x - axis in anti-clockwise direction.

It means,

  • Line AC makes an angle of 90° with positive direction of x - axis.

Now,

We know that

Equation of line which passes through the point (a, b) and having slope m, then equation of line is given by

\bf :\longmapsto\:y - b = m(x - a)

So,

Equation of AC which passes through the point (3, 0) and makes an angle of 90° with positive direction of x axis is

\rm :\longmapsto\:y - 0 = tan90\degree (x - 3)

\rm :\longmapsto\:y = \dfrac{1}{0}(x - 3)

\bf\implies \:x = 3

Let

  • Coordinates of point C be (x, y).

As x = 3

Therefore,

  • Coordinates of C = (3, y)

As

  • AB is rotated through an angle of 45° and took new pisition AC.

It means

  • Length of AB = Length of AC

\rm :\longmapsto\:AB = AC

\rm :\longmapsto\: {AB}^{2}  =  {AC}^{2}

\rm :\longmapsto\: {(5 - 3)}^{2} +  {(2 - 0)}^{2} =  {(3 - 3)}^{2} +  {(y - 0)}^{2}

\rm :\longmapsto\:4 + 4 =  {y}^{2}

\rm :\longmapsto\:8 =  {y}^{2}

\bf\implies \:y =  \sqrt{8} =  \sqrt{2 \times 2 \times 2}  = 2 \sqrt{2}

Hence,

\bf :\longmapsto\:Coordinates \:  of  \: C = (3,2 \sqrt{2})

Now,

We know that

Reflection of Coordinates C under y - axis is obtained by changing the sign of x - coordinate.

So,

\bf :\longmapsto\:Coordinates \:  of  \: D= ( - 3, 2 \sqrt{2})

Attachments:
Answered by tammarapuaditya
0

Step-by-step explanation:

-3,2,root2

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