Question

The line segment joining the points (3, -1) and (-6, 5) is trisected. The coordinates of one of the point of trisection are​

Answer 1

Answer:

Here AP:PQ:QB=1:1:1

AP:PB = 1:2

Thus X1=1*-6+2*3/1+2

=-6+6/2=0/2=0

&y1=1*5+2*-1/1+2

=5-2/3=3/3=1

Therefore,now Q is the mid point of P(0,1)&B(-6,5)

Therefore, Q(X2,Y2)=(1*-6+2*0/1+2 , 1*5+2*1/1+2)

=(-6+2/3 , 5+2/3). = (-4/3 , 7/3