Question

The line segment joining the points A(2,1) and B(5,-8) is trisected at the points P and Q such that p is nearest to A if P is also lies on the line given by 2x-y+k=0 find the value of K ​

Answer 1

Answer:

lol

Step-by-step explanation:

Answer 2

Answer:

k = -8

Step-by-step explanation:

The line segment is divided into 3 equal parts 1:1:1.

:. P divides the line into 1:2.

A(2,1) x1= 2 y1= 1

B(5,-8) x2= 5 y2= -8

P(x,y) m1= 1 m2=2

USING SECTION FORMULA P(x,y) = m1x2+m2x1/m1+m2 , m1y2 + m2y1/m1+m2

= 1(5)+2(2)/3 , 1(-8)+2(1)/3

= 5+4/3, -8+2/3

= 3, -2

x=3 and y= -2

2x-y+k=0

2(3)-(-2)+k=0

6+2+k=0

8+k=0

k= -8

HOPE IT IS CLEAR

PLS MARK AS BRAINLIEST.