Math, asked by areebatejani, 3 months ago

The line y = ax + b is perpendicular to the line y - 3x = 4 and passes
through the point (1, -2). The value of 'a' an of'b' are:
A
C.
a = -1/3 , b = 5/3
a = 1/3, b = 5/3
B.
D.
a = 1/3, b = -5/3
a = -1/3 , b = -5/3​

Answers

Answered by kundanconcepts800
1

Answer:

a= -1/3, b= -5/3

Step-by-step explanation:

slope of line y =ax+b is given by m= a

and slope of line y= 3x+4 is given by m' = 3

since, they're perpendicular

hence, a= -1/3

So, the line y= (-1/3)x +b .

this line passes through (1,-2)

hence , ( -2 ) = (-1/3)×1 +b

or , b = 1/3 - 2 = -5/3

Answered by Aarav9821
2

Answer:

Let P and Q are two lines having equations y=ax+b and y-3x=4 respectively.

Both these lines are perpendicular .

So the product of slope of these lines must be equal to -1.

Slope of line P is a

Slope of line Q is 3

Now 3a=(-1)

So a=(-1/3)

Also it is given that line P passes through the point (1,-2)

So -2 = (-1/3)1 + b

Or b = (1/3)-2

Or b = (-5/3)

So your answer is a=(-1/3) and b=(-5/3)

If my answer satisfies you then plz give me thanks.

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