Question

The line y=mx+4 passes through the points (3, log2p) and (log2p,4). what are the possible values of p?
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Answer 1

Answer:

Idk sorry im just new it's OK :)

Answer 2

Answer:

p=1

Step-by-step explanation:

∵(3, log2p) and (log2p,4) passes thru y=mx+c

(3, log2p) and (log2p,4) satisfies y=mx +c

∴log2p=m.3+4 ------(i)

& 4=m(log2p)+4-----(ii)

on solving(ii)

m.log2p=4-4=0

log2p=0

p=$2^{0}$=1