The linear equation that converts Fahrenheit to Celsius is given by the relation
C = 5F-160/9
What is the numerical value of the temperature which is same in both scales ?
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We have
C = (5F - 160)/9 .....(i)
Now we put C = F in (i) and we get
F = (5F - 160)/9
or, 9F = 5F - 160
or, 4F = -160
or, F = -40
So, F = C = -40°.
Therefore (-40) is the numerical value of the temperature which is same in both scales.
We have
C = (5F - 160)/9 .....(i)
Now we put C = F in (i) and we get
F = (5F - 160)/9
or, 9F = 5F - 160
or, 4F = -160
or, F = -40
So, F = C = -40°.
Therefore (-40) is the numerical value of the temperature which is same in both scales.
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