Question

The linear magnification produced by a spherical mirror is -1/5. Analysing this value, state the position of the object with respect to the pole of the mirror . Draw the ray diagram to justify

Answer 1

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Answer 2

Answer:

The mirror is concave.

Because the modulus value of m is much less than 1, the nature of the image is real & inverted.

$m=-\frac{1}{5} =\frac{h_{i} }{h_{0} } =\frac{v}{u}$

According to the aforementioned formula, the object's height is five times that of its image, and its distances from the light's pole is five times that of its image.

Explanation:

According to the topic, the spherical mirror's linear magnifying is m= 1/ 5; as a result, the magnification is only negatives in the case of a

concave mirror and for both the real and inaccurate and unreliable. The linear magnification's equation as follows:

 $m=-\frac{1}{5} =\frac{h_{i} }{h_{0} } =\frac{v}{u}$

h 1 = image height

h 0 = the object's height

u = distance of the item

v = distance of the image

According to this equation, the element's elevation is five times greater than that of its image, and its range from of the mirror's pole is five times higher than that of its image in enlargement. The ratio of the picture length to the item length, as evaluated in planes perpendicular to the optical axis, is referred to as linear magnification, also known as lateral or longitudinal optical zoom. An misleading picture is shown by a linear magnifying value that is negative.

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