Physics, asked by gurulingamurthy1234, 10 months ago

the linear momentum of particle P is equals to a + b find force acting on particle​

Answers

Answered by nishantsaxena53
1

#BAL

Linear momentum is a product of the mass (m) of an object and the velocity (v) of the object. If an object has higher momentum, then it harder to stop it. The formula for linear momentum is p = mv. The total amount of momentum never changes, and this property is called conservation of momentum. Let us study more about Linear momentum and conservation of momentum.

We know that the linear momentum of the particle is

p = mv

Newton’s second law for a single particle is given by,

F = dPdt

where F is the force of the particle. For ‘ n ‘ no. of particles total linear  momentum is,

P = p1 + p2 +…..+pn

each of momentum is written as  m1 v1 + m2v2 + ………..+mnvn. We know that velocity of the centre of mass is V =  Σ  miviM,

mv =  Σ  mivi

So comparing these equations we get,

P = M V

Therefore we can say that the total linear momentum of a system of particles is equal to the product of the total mass of the system and the velocity of its center of mass. Differentiating the above equation we get,

dPdt = M dVdt = MA

dv/dt is acceleration of centre of mass, MA is the force external. So,

dPdt = Fext

This above equation is nothing but Newton’s second law to a system of particles. If the total external force acting on the system is zero,

Fext = 0 then, dPdt = 0

This means that P = constant. So whenever the total force acting on the system of a particle is equal to zero then the total linear momentum of the system is constant or conserved. This is nothing but the law of conservation of total linear momentum of a system of particles.

Browse more Topics under System Of Particles And Rotational Dynamics

Introduction to Rotational Dynamics

Vector Product of Two Vectors

Centre of Mass

Motion of Centre of Mass

Moment of Inertia

Theorems of Parallel and Perpendicular Axis

Rolling Motion

Angular Velocity and Angular Acceleration

Torque and Angular Momentum

Equilibrium of a Rigid Body

Angular Momentum in Case of Rotation About a Fixed Axis

Dynamics of Rotational Motion About a Fixed Axis

Kinematics of Rotation Motion about a Fixed Axis

Conservation of Total Linear Momentum of a System of Particles

Let us take the example of radioactive decay. What is radioactive decay? It is a process where an unstable nucleus splits up in relatively stable nuclei releasing a huge amount of energy.

Suppose there is a parent nucleus which is unstable and it wants to become stable, in order to attain stability it will emit α particle and another daughter nucleus.

This daughter nucleus is much more stable than the parent nucleus. This what radioactive decay is. Now suppose the parent nucleus is at rest and also the mass of the α is ‘ m ‘ and the daughter nucleus is M.

So the mass of the parent nucleus will be m + M. Here everything that is happening is not due to the external force but all that happens is due to the internal force. So here Fext = 0, we can say that

dPdt = 0 ⇒ P = constant

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