The lines 2x+3y+1=0 , 6x+4y+1=0 intersect the co-ordinate axes in 4 points ,then the circle passing through the points is
Answers
Given : the lines 2x+3y+1=0 and 6x+4y+1=0 intersect the co-ordinate axes in 4 points,
To Find : the circle passing through the points
Solution:
2x + 3y + 1 = 0
x = 0 => y = -1/3
y = 0 => x = - 1/2
Points are
( 0 , - 1/3) and ( -1/2 , 0)
6x+4y+1=0
x = 0 => y = -1/4
y = 0 => x = - 1/6
Points are
( 0 , - 1/4) and ( -1/6 , 0)
Find perpendicular bisector of both the lines above and from intersection find centers
find distance between center and any point to find radius
(x - h)² + (y - k)² = r²
on solving get :
12x² + 12y² + 8x + 7y + 1 = 0 is the required equation
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