Question

what is the resultant ph of mixture of two solutions having ph=6 and ph=8 with equal volume?​

Answer 1

Let x be the volume of both solution

Here's for first solution,

pH = 6 then M1= 10^-6

For second solution,

pH = 8 , so M2 = 10^-8

M1V1 + M2V2 = MV

10^-6×x + 10^-8x = M(x+x)

x(10^-6 + 10^-8) = 2x.M

M = (10^-6 + 10^-8)/2

M = 5.05 × 10^-7

Now taking log ans will come 6.297

pH = 6.297