Question

The lines drawn from A and C of a pair of parallel lines AB and CD meet each other at O between AB and CD. If ∠DCO =130˚ and ∠OAB=110˚, find ∠AOC

Very urgent pls​

Answer 1

To Find

Find ∠AOC

Given:-

If ∠DCO =130˚ and ∠OAB=110˚

Solution:-

step-by-step explanation:

Through O draw a line EOF which is parallel to AB.

Now, EF || AB and AO is a transversal.

So, we have

∠AOF + ∠OAB = 180 degree.

∠AOF + 110° = 180 degree.

∠AOF = 180 - 110

∠AOF = 70°

Now, EF || CD and OC is Transversal.

So,

∠COF + ∠OCD = 180 degree.

∠COF + 130° = 180 degree

∠COF = 180 - 130

∠COF = 50°

Then,

∠AOC = ∠AOF + ∠COF

∠AOC = 70 + 50

∠AOC = 120°

An attachment is given of diagram of the sum.

Required Answer

∠DCO =130˚, ∠OAB=110˚ and ∠AOC=120°

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some important concepts:

1. A supplementary angle measures 180 degree.

2. A complementary angle measures 180 degree.

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