Question

The lines x=3 ,y=-1/2(x+1) and
y=2/3 x+3 form the sides of triangle.
Find the area of triangle.

please somebody answer​

Answer 1

Answer:

x

2

−y

2

+2y=1

x

2

=(y−1)

2

Hence, the two lines are =

y=−x+1 and y=x+1

Equation of angle bisectors of these lines

x=0 and y=1

Intersection between the 3 lines is

A(0,3),B(0,1),C(2,1)

It can be seen that as the points A and B lie on y-axis only and BC is parallel to x-axis. Hence, △ABC is a right angled triangle.

Area=

2

1

×AB×BC

⟹

2

1

×2×2

⟹2

Answer 2

Answer:

Your answer will be :-

AB × BA

2 × 2

= 4