Question

The lines x=3 ,y=-1/2(x+1) and
y=2/3 x+3 form the sides of triangle.
Find the area of triangle.

please somebody answer​ And I need correct answer plsss​

Answer 1

Answer:

) 2 sq units

Step-by-step explanation:

To find B

3x−2y=−1 and x+y=3

solving above two equations we get

y=2 and x=1

B=(1,2)

To find C

3x−2y=−1 and x−3y=−9

solving above two equations we get

y=27/6 and x=15/7

C=(

7

15

,

6

27

)

s=

2

perimeteroftriangle

a=AB=

(1−0)

2

+(2−3)

2

=

1+1

=

2

b=BC=

(

7

15

−1)

2

+(

7

26

−2)

2

=

(

7

8

)

2

+(

7

12

)

2

=

7

4

13

c=CA=

(

7

15

−0)

2

+(

7

26

−3)

2

=

(

7

15

)

2

+(

7

5

)

2

=

7

5

10

s=

2

a+b+c

s=

2

2

+

7

4

13

+

7

5

10

s=

14

14

2

+4

13

+5

10

s−a=

14

−7

2

+4

13

+5

10

s−b=

14

14

2

−4

13

+5

10

s−c=

14

14

2

+4

13

−5

10

A=

s(s−a)(s−b)(s−c)

A=

(

14

−7

2

+4

13

+5

10

)(

14

14

2

−4

13

+5

10

)(

14

14

2

+4

13

−5

10

)

Multiplying and solving

A=

7

16

sq unit

solution