Question

The lines x+y=|a| and ax-y=1 intersect each other in the first quadrant. Then, the set of all possible values of a in the interval is?

Answer 1

x + y = lal
ax - y = 1

Equations solved simultaneously
x = lal + 1 ÷ 1 + a,  y = a lal -1 ÷ 1 + a

Both equations fall in the first quadrant so both are greater than zero.
1 + a > 0 and a lal - 1 >0

After solving the answer is a > 1
So all possible values of a are in the interval
a ∈ (1, ∞)

Answer 2

Answer:

the answer is a E (1, infinite).

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