The locus of the orthocentre of the triangle formed by the lines and , where , is:
a a hyperbola
b a parabola
c an ellipse
d a straight line
#33380
the maximum area of the rectangle that can be inscribed in the circle given by in sq. Units is
a
b
c
d
#33628
the set of all points where is not differentiable is
a
b
c
d none of these
= =
x + 2
2
y + 1
â1
z
3
x + y + z = 3
= =
x
5
y â 1
8
z â 2
â13
= =
x
2
y â 1
3
z â 2
â5
= =
x
4
y â 1
3
z â 2
â7
= =
x
2
y â 1
â7
z â 2
5
cot(â (1 + 2k))
n=1
23
cotâ1 â
k=1
n
23
25
25
23
23
24
24
23
(1 + p)x â py + p(1 + p)
Answers
Answered by
0
D is the correct answer im a beginner but i still got skills
Answered by
0
Thank you for asking this question. Here is your answer:
The correct answer for this question is option D: Straight Line
The intersection point of y = 0 with first line is B(-p, 0)
The intersection point of y = 0 with second line is Q(-q, 0)
The intersection point of the two line is C(p q,(p + 1)(q + 1))
And the altitude from C to AB is x = p q
Altitude from B to AC is y = q/1+q (x+p)
When we will solve these we will get
x = p q and y = -p q
locus of or thocentre is x + y = 0
So this is a straight line.
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