the locus of the point whic is at a distance 5unit from x-axis is
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Let our point be (x,y)
Distance of any point from x-axis = magnitude of its y coordinate
From the question we have,
Distance of any point from x-axis =5
Which implies that
∣ y ∣ =5
Now squaring each side we get
y *2 =25 which can be re-written as
y* 2 −25=0
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