Physics, asked by saumyabaranwal2223, 1 year ago

The longitudinal waves starting from a ship returns from the bottom of the sea to the ship after 2.64 seconds. If the bulk modulus of water be 220kg/mm2 and density 1.1*10to the power 3 kg/m3 then calculate the depth of the sea
g=9.8N/kg

Answers

Answered by lidaralbany
18

Answer: The depth of the sea is 1848 m

Explanation:

Given that,

Bulk modulus K = 220 kg/mm^{2}

Time t = 2.64 sec

Density \rho = 1.1\times10^{3} kg /m^{3}

We know that,

The velocity is

v = \sqrt{\dfrac{K}{\rho}}

v = \sqrt{\dfrac{220\times9.8 N/ m^{2}}{10^{-6}\times 1.1\times10^{3}kg/m^{3}}}

The depth of the sea is

2d = v\times t

d = \sqrt{\dfrac{220\times9.8 N/ m^{2}}{10^{-6}\times 1.1\times10^{3}kg/m^{3}}} \times 1.32s

d = 1848 m

Hence, the depth of the sea is 1848 m.

Similar questions