Math, asked by sharanabasavame5955, 9 months ago

The Lord. C.L.M of 1÷3,5÷6,2÷9,4÷27 is

Answers

Answered by sanjana5676

1

Answer:

LCM of fractions = (LCM of numerators) / (HCF of denominators)

∴ Required LCM = (LCM of 1, 2, 5, and 4) / (HCF of 3, 9, 6 and 27)

∴ = 20/3

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