The loss in weight of a body taken from earth's surface to a height h is 1 percentage the change in weight then into a mine of depth h will be
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Answer:
given :
mass= m kg
height =h m
acceleration due to gravity=g m/s2
Acceleration due to gravity at height H IS GIVEN BY :
g¹=g(1-2h/R)
Loss of weight =ΔW=mg-mg¹
=m[g-g¹]
=m[g-g(1-2h/R)]
=mg[1-(1-2h/R)]
=mg[1-1+2h/R]
=mg x 2h/R
=2mgh/R
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