Question

the lowest pitch detectable as sound by an average human car corresponds to 20 Hz and the highest to 20000 Hz what is the wavelength of each in air? Take velocity of sound as 330 M /s-1​

Answer 1

wavelength= velocity/frequency

(1). wavelength=

$330 \div 20 = 16.5m$

(2). wavelength=

$330 \div 20000 = 0.0165m$

Answer 2

The wavelength corresponding to each frequencies are 16.5 m and 0.0165 m.

Explanation:

The lowest pitch of the human ear, $f_1=20\ Hz$

The highest pitch of the human ear, $f_2=20000\ Hz$

The speed of sound, v = 330 m/s

We need to find the wavelength corresponding to each frequencies. It is given by :

$\lambda_1=\dfrac{v}{f_1}$

$\lambda_1=\dfrac{330\ m/s}{20\ Hz}$

$\lambda_1=16.5\ m$

Similarly,

$\lambda_2=\dfrac{v}{f_2}$

$\lambda_2=\dfrac{330\ m/s}{20000\ Hz}$

$\lambda_2=0.0165\ m$

So, the wavelength corresponding to each frequencies are 16.5 m and 0.0165 m. Hence, this is the required solution.

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