Physics, asked by saikireeti5856, 1 year ago

The magnetic field in a plane electromagnetic wave is given by By=2×10−7sin(0.5×103x+1.5×1011t)T The wavelength and frequency of the wave are

Answers

Answered by shankarpatel83054
0

Answer:

09887765865556.7655

Answered by sanjeevk28012
3

Answer:

The wavelength of wave is 1.25 cm

The frequency of wave 23.8 GHz  

Explanation:

The magnetic field in a plane electromagnetic wave is given as

y = 2 × 10^{-7} Sin ( 0.5 × 10³ x + 1.5 × 10^{11} t ) T

Comparing the given equation with

B_y = B_0  sin [2 π ( (x/ λ) + (t/T) )]

i.e B_0 = 2 × 10^{-7}

And  λ =  \dfrac{2 \Pi }{0.5\times 10^{3}}  meters

i.e λ =  0.01256 m

Or, λ = 1.25 cm

So, The wavelength = λ = 1.25 cm

Again

\dfrac{1}{T} =  \dfrac{1.5\times 10^{11}}{2\Pi }

frequency = f = \dfrac{1}{T}

So, f = \dfrac{1.5\times 10^{11}}{2\Pi }  Hz

or, f = 2.38 × 10^{10}

i.e frequency = f = 23.8 GHz

Hence, The wavelength of wave is 1.25 cm

And  The frequency of wave 23.8 GHz  Answer

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